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<feed xmlns="http://www.w3.org/2005/Atom"><title>blog.bernatchez.net - calculus</title><link href="https://blog.bernatchez.net/lang-version.en/" rel="alternate"/><link href="https://blog.bernatchez.net/lang-version.en/feeds/calculus.atom.xml" rel="self"/><id>https://blog.bernatchez.net/lang-version.en/</id><updated>2026-05-19T02:21:52+00:00</updated><entry><title>IB Calculus Problem 1</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq1-en.html" rel="alternate"/><published>2026-05-19T02:21:52+00:00</published><updated>2026-05-19T02:21:52+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq1-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus Problem 1&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let the function &lt;span class="math"&gt;\(f(x) = 6x^2-3x\)&lt;/span&gt; be represented below.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image that is essential to understanding the question" src="../images/6xsq-3x.png" /&gt;
&lt;/div&gt;
&lt;ol class="upperalpha"&gt;
&lt;li&gt;&lt;p class="first"&gt;Find &lt;span class="math"&gt;\(\int \! (6x^2-3x) \, \mathrm{d}x\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;Find the area of the region bounded by the graph of &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt;,&lt;/p&gt;
&lt;p&gt;the x-axis and the lines &lt;span class="math"&gt;\(x = 1\)&lt;/span&gt; and &lt;span class="math"&gt;\(x = 2\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;That is, &lt;span class="math"&gt;\(\int_1^2 \! (6x^2-3x) \, \mathrm{d}x\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 2</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq2-en.html" rel="alternate"/><published>2026-05-19T02:21:50+00:00</published><updated>2026-05-19T02:21:50+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq2-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus Problem 2&lt;/p&gt;
</summary><content type="html">&lt;p&gt;A closed cylindrical metal box has a radius of &lt;span class="math"&gt;\(r\)&lt;/span&gt; centimetres and a height of &lt;span class="math"&gt;\(h\)&lt;/span&gt; centimetres, with a volume of &lt;span class="math"&gt;\(20\pi\, cm^3\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image that is essential to understanding the question" src="../images/cylindre.png" /&gt;
&lt;/div&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Express &lt;span class="math"&gt;\(h\)&lt;/span&gt; in terms of &lt;span class="math"&gt;\(r\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;div class="line-block"&gt;
&lt;div class="line"&gt;&lt;br /&gt;&lt;/div&gt;
&lt;/div&gt;
&lt;p&gt;The metal for the base and lid of the box costs 10 cents per &lt;span class="math"&gt;\(cm^2\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The metal for the curved side costs &lt;span class="math"&gt;\(8\)&lt;/span&gt; cents per &lt;span class="math"&gt;\(cm^2\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The total cost of the metal, in cents, is &lt;span class="math"&gt;\(C\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple" start="2"&gt;
&lt;li&gt;Show that &lt;span class="math"&gt;\(C\,=\,20\pi{}r^2 + \frac{320\pi}{r}\)&lt;/span&gt;&lt;/li&gt;
&lt;li&gt;Given that a minimum value of &lt;span class="math"&gt;\(C\)&lt;/span&gt; exists, find this minimum value in terms of &lt;span class="math"&gt;\(\pi\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 3</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq3-en.html" rel="alternate"/><published>2026-05-19T02:21:48+00:00</published><updated>2026-05-19T02:21:48+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq3-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 3&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Consider a function &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt;. The line &lt;span class="math"&gt;\(L_1\)&lt;/span&gt; with equation &lt;span class="math"&gt;\(y = 3x + 1\)&lt;/span&gt; is tangent to the graph of &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt; at &lt;span class="math"&gt;\(x = 2\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;&lt;ol class="first lowerroman"&gt;
&lt;li&gt;Write down &lt;span class="math"&gt;\(f^\prime(2)\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find &lt;span class="math"&gt;\(f(2)\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;/li&gt;
&lt;/ol&gt;
&lt;p&gt;Let &lt;span class="math"&gt;\(g(x) = f(x^2 + 1)\)&lt;/span&gt; and let &lt;span class="math"&gt;\(P\)&lt;/span&gt; be the point on the graph of &lt;span class="math"&gt;\(g\)&lt;/span&gt; where &lt;span class="math"&gt;\(x = 1\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple" start="2"&gt;
&lt;li&gt;Show that the graph of &lt;span class="math"&gt;\(g\)&lt;/span&gt; has a slope of 6 at point &lt;span class="math"&gt;\(P\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;p&gt;Let &lt;span class="math"&gt;\(L_2\)&lt;/span&gt; be the tangent to the graph of &lt;span class="math"&gt;\(g\)&lt;/span&gt; at point &lt;span class="math"&gt;\(P\)&lt;/span&gt;. &lt;span class="math"&gt;\(L_1\)&lt;/span&gt; intersects &lt;span class="math"&gt;\(L_2\)&lt;/span&gt; at point &lt;span class="math"&gt;\(Q\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple" start="3"&gt;
&lt;li&gt;Find the y-coordinate of &lt;span class="math"&gt;\(Q\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 4</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq4-en.html" rel="alternate"/><published>2026-05-19T02:21:46+00:00</published><updated>2026-05-19T02:21:46+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq4-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 4&lt;/p&gt;
</summary><content type="html">&lt;p&gt;The following figure shows the graph of &lt;span class="math"&gt;\(f(x) = a\,Cos\,bx\)&lt;/span&gt;,
for &lt;span class="math"&gt;\(0 \leq x \leq 4\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image that is essential to understanding the question" src="../images/temp_cos_wave.png" /&gt;
&lt;/div&gt;
&lt;p&gt;There is a minimum point at &lt;span class="math"&gt;\(P( 2, -3 )\)&lt;/span&gt; and a maximum point at &lt;span class="math"&gt;\(Q( 4, 3 )\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;&lt;ol class="first lowerroman"&gt;
&lt;li&gt;State the value of &lt;span class="math"&gt;\(a\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find the value of &lt;span class="math"&gt;\(b\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;/li&gt;
&lt;li&gt;State the gradient of the curve at &lt;span class="math"&gt;\(P\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;State the equation of the normal to the curve at &lt;span class="math"&gt;\(P\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 5</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq5-en.html" rel="alternate"/><published>2026-05-19T02:21:45+00:00</published><updated>2026-05-19T02:21:45+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq5-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 5&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(h(x) = \frac{6x}{cos x}\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Find &lt;span class="math"&gt;\(h^\prime(0)\)&lt;/span&gt;.&lt;/p&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 6</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq6-en.html" rel="alternate"/><published>2026-05-19T02:21:44+00:00</published><updated>2026-05-19T02:21:44+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq6-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 6&lt;/p&gt;
</summary><content type="html">&lt;p&gt;The following figure shows part of the graph of &lt;span class="math"&gt;\(f(x) = 2x\sqrt[2]{a^2 - x^2}\)&lt;/span&gt;, for &lt;span class="math"&gt;\(-1 \leq x \leq a\)&lt;/span&gt;, where &lt;span class="math"&gt;\(a &amp;gt; 1\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/temp_2xsqrtasq-xsq.png" /&gt;
&lt;/div&gt;
&lt;p&gt;The line &lt;span class="math"&gt;\(L\)&lt;/span&gt; is the tangent to the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; at the origin, &lt;span class="math"&gt;\(O\)&lt;/span&gt;.
The point &lt;span class="math"&gt;\(P(a; b)\)&lt;/span&gt; is on &lt;span class="math"&gt;\(L\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Given that &lt;span class="math"&gt;\(f^\prime(x) =\frac{2a^2 - 4x^2}{\sqrt{a^2-x^2}}\)&lt;/span&gt;, for &lt;span class="math"&gt;\(-1 \leq x \leq a\)&lt;/span&gt;, find the equation of &lt;span class="math"&gt;\(L\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Hence or otherwise, find an expression for &lt;span class="math"&gt;\(b\)&lt;/span&gt; in terms of &lt;span class="math"&gt;\(a\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 7</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq7-en.html" rel="alternate"/><published>2026-05-19T02:20:02+00:00</published><updated>2026-05-19T02:20:02+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq7-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 7&lt;/p&gt;
</summary><content type="html">&lt;p&gt;The following figure shows part of the graph of the function &lt;span class="math"&gt;\(f(x) = 2x^2\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/temp_f_2xsquared.png" /&gt;
&lt;/div&gt;
&lt;p&gt;The line &lt;span class="math"&gt;\(T\)&lt;/span&gt; is the tangent to the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; at &lt;span class="math"&gt;\(x = 1\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Show that the equation of &lt;span class="math"&gt;\(T\)&lt;/span&gt; is &lt;span class="math"&gt;\(y = 4x - 2\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find the x-intercept of &lt;span class="math"&gt;\(T\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;The shaded region &lt;span class="math"&gt;\(R\)&lt;/span&gt; is bounded by the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt;, the line &lt;span class="math"&gt;\(T\)&lt;/span&gt; and the x-axis.&lt;ol class="lowerroman"&gt;
&lt;li&gt;Write down an expression for the area of &lt;span class="math"&gt;\(R\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find the area of &lt;span class="math"&gt;\(R\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 8</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq8-en.html" rel="alternate"/><published>2026-05-19T02:18:27+00:00</published><updated>2026-05-19T02:18:27+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq8-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 8&lt;/p&gt;
</summary><content type="html">&lt;p&gt;The following figure shows part of the graph of the quadratic function &lt;span class="math"&gt;\(f\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/temp_down_parabola.png" /&gt;
&lt;/div&gt;
&lt;p&gt;The x-intercepts are at &lt;span class="math"&gt;\(( -4; 0 )\)&lt;/span&gt; and &lt;span class="math"&gt;\(( 6; 0 )\)&lt;/span&gt; and the y-intercept is at &lt;span class="math"&gt;\(( 0; 240 )\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Write down &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt; in the form &lt;span class="math"&gt;\(f(x) = -10(x - p) (x - q)\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find another expression for &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt; in the form &lt;span class="math"&gt;\(f(x) = -10(x - h)^2 + k\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Show that &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt; can also be written as &lt;span class="math"&gt;\(f(x) = 240 + 20x -10x^2\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;A particle moves in a straight line such that its velocity &lt;span class="math"&gt;\(v\)&lt;/span&gt; ( in &lt;span class="math"&gt;\(ms^{-1}\)&lt;/span&gt; ),
at time &lt;span class="math"&gt;\(t\)&lt;/span&gt; (in seconds), is given by &lt;span class="math"&gt;\(v = 240 + 20t -10t^2\)&lt;/span&gt; , for &lt;span class="math"&gt;\(0 \leq t \leq 6\)&lt;/span&gt;.&lt;ol class="lowerroman"&gt;
&lt;li&gt;Find the value of &lt;span class="math"&gt;\(t\)&lt;/span&gt; when the velocity of the particle is greatest.&lt;/li&gt;
&lt;li&gt;Find the acceleration of the particle when its velocity is zero.&lt;/li&gt;
&lt;/ol&gt;
&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 9</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq9-en.html" rel="alternate"/><published>2026-05-19T02:17:12+00:00</published><updated>2026-05-19T02:17:12+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq9-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 9&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(f(x) = kx^4\)&lt;/span&gt;. The point &lt;span class="math"&gt;\(P(1 ; k)\)&lt;/span&gt; is on the curve of &lt;span class="math"&gt;\(f\)&lt;/span&gt;.
At &lt;span class="math"&gt;\(P\)&lt;/span&gt;, the normal to the curve is parallel to &lt;span class="math"&gt;\(y = -\frac{1}{8}x\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Find the value of &lt;span class="math"&gt;\(k\)&lt;/span&gt;.&lt;/p&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 10</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq10-en.html" rel="alternate"/><published>2026-05-19T02:14:08+00:00</published><updated>2026-05-19T02:14:08+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq10-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 10&lt;/p&gt;
</summary><content type="html">&lt;p&gt;A function &lt;span class="math"&gt;\(f\)&lt;/span&gt; is defined for &lt;span class="math"&gt;\(-4 \leq x \leq 3\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; is shown below.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/temp_polynom_minus4_to_3.png" /&gt;
&lt;/div&gt;
&lt;p&gt;The graph has a local maximum at &lt;span class="math"&gt;\(x = 0\)&lt;/span&gt; and local minima at &lt;span class="math"&gt;\(x = -3\)&lt;/span&gt; and &lt;span class="math"&gt;\(x = 2\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha"&gt;
&lt;li&gt;&lt;p class="first"&gt;Write down the x-intercepts of the graph of the derivative function, &lt;span class="math"&gt;\(f^\prime\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;Write down all values of &lt;span class="math"&gt;\(x\)&lt;/span&gt; for which &lt;span class="math"&gt;\(f^\prime(x)\)&lt;/span&gt; is positive.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;At point &lt;span class="math"&gt;\(D\)&lt;/span&gt; on the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt;, the x-coordinate is &lt;span class="math"&gt;\(-0.5\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Explain why &lt;span class="math"&gt;\(f^{\prime\prime}(x) &amp;lt; 0\)&lt;/span&gt; at &lt;span class="math"&gt;\(D\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 11</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq11-en.html" rel="alternate"/><published>2026-05-19T02:12:44+00:00</published><updated>2026-05-19T02:12:44+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq11-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 11&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Consider the function &lt;span class="math"&gt;\(f\)&lt;/span&gt; whose second derivative is &lt;span class="math"&gt;\(f^{\prime\prime}(x) = 3x -1\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; has a minimum point at &lt;span class="math"&gt;\(A(2 ; 4)\)&lt;/span&gt; and a maximum point at &lt;span class="math"&gt;\(B(-\frac{4}{3}; \frac{358}{27})\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Use the second derivative to justify that &lt;span class="math"&gt;\(B\)&lt;/span&gt; is a maximum.&lt;/li&gt;
&lt;li&gt;Given that &lt;span class="math"&gt;\(f^\prime(x) = \frac{3}{2}x^2 - x + p\)&lt;/span&gt;, show that &lt;span class="math"&gt;\(p = -4\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 12</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq12-en.html" rel="alternate"/><published>2026-05-19T02:07:34+00:00</published><updated>2026-05-19T02:07:34+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq12-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 12&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(f(x) = 6 + 6\,sin\,x\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Part of the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; is shown below.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/temp_6_plus_6sinx.png" /&gt;
&lt;/div&gt;
&lt;p&gt;The shaded region is bounded by the curve of &lt;span class="math"&gt;\(f\)&lt;/span&gt;, the x-axis and the y-axis.&lt;/p&gt;
&lt;p&gt;The path makes an angle of &lt;span class="math"&gt;\(4^\circ\)&lt;/span&gt; with the horizontal.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Solve, for &lt;span class="math"&gt;\(0 \leq x \leq 2\pi\)&lt;/span&gt;&lt;ol class="lowerroman"&gt;
&lt;li&gt;&lt;span class="math"&gt;\(6 + 6\,sin\,x = 6\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;&lt;span class="math"&gt;\(6 + 6\,sin\,x = 0\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;/li&gt;
&lt;li&gt;Write down the exact value of the x-intercept of &lt;span class="math"&gt;\(f\)&lt;/span&gt;, for &lt;span class="math"&gt;\(0 \leq x \leq 2\pi\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;The area of the shaded region is &lt;span class="math"&gt;\(k\)&lt;/span&gt;. Find the value of &lt;span class="math"&gt;\(k\)&lt;/span&gt;, giving your answer in terms of &lt;span class="math"&gt;\(\pi\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;p&gt;Let &lt;span class="math"&gt;\(g(x) = 6 + 6\,sin\,(x - \frac{\pi}{2})\)&lt;/span&gt;. The graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; is transformed to that of &lt;span class="math"&gt;\(g\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple" start="4"&gt;
&lt;li&gt;Give a full geometric description of this transformation.&lt;/li&gt;
&lt;li&gt;Given that &lt;span class="math"&gt;\(\int_p^{p+\frac{3\pi}{2}}g(x)\,dx = k\)&lt;/span&gt; and &lt;span class="math"&gt;\(0 \leq p &amp;lt; 2\pi\)&lt;/span&gt;, write down the two values of &lt;span class="math"&gt;\(p\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 13</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq13-en.html" rel="alternate"/><published>2026-05-19T02:04:07+00:00</published><updated>2026-05-19T02:04:07+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq13-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 13&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(f^\prime(x) = 12x^2 - 2\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Given that &lt;span class="math"&gt;\(f(-1) = -1\)&lt;/span&gt;, find &lt;span class="math"&gt;\(f(x)\)&lt;/span&gt;.&lt;/p&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 14</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq14-en.html" rel="alternate"/><published>2026-05-19T02:00:55+00:00</published><updated>2026-05-19T02:00:55+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-19:/lang-version.en/calculusq14-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 14&lt;/p&gt;
</summary><content type="html">&lt;p&gt;The velocity &lt;span class="math"&gt;\(v\)&lt;/span&gt;, in &lt;span class="math"&gt;\(ms^{-1}\)&lt;/span&gt;, of a particle moving in a straight line is given by &lt;span class="math"&gt;\(v=e^{3t-2}\)&lt;/span&gt;, where &lt;span class="math"&gt;\(t\)&lt;/span&gt; is the time in seconds.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Find the acceleration of the particle at time &lt;span class="math"&gt;\(t = 1\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;For what value of &lt;span class="math"&gt;\(t\)&lt;/span&gt; does the particle have a velocity of &lt;span class="math"&gt;\(22.3ms^{-1}\)&lt;/span&gt;?&lt;/li&gt;
&lt;li&gt;Find the distance travelled during the first second.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 15</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq15-en.html" rel="alternate"/><published>2026-05-18T20:11:31+00:00</published><updated>2026-05-18T20:11:31+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq15-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 15&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(f(x) = 3 Cos2x + Sin^2x\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha"&gt;
&lt;li&gt;&lt;p class="first"&gt;Show that &lt;span class="math"&gt;\(f^\prime(x) = -5Sin2x\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;In the interval &lt;span class="math"&gt;\(\frac{\pi}{4} \leq x \leq \frac{3\pi}{4}\)&lt;/span&gt;,
a normal to the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; has equation &lt;span class="math"&gt;\(x = k\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Find the value of &lt;span class="math"&gt;\(k\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 16</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq16-en.html" rel="alternate"/><published>2026-05-18T20:09:52+00:00</published><updated>2026-05-18T20:09:52+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq16-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 16&lt;/p&gt;
</summary><content type="html">&lt;p&gt;A particle &lt;span class="math"&gt;\(P\)&lt;/span&gt; moves along a straight line. The velocity &lt;span class="math"&gt;\(v\)&lt;/span&gt; &lt;span class="math"&gt;\(ms^{-1}\)&lt;/span&gt; of &lt;span class="math"&gt;\(P\)&lt;/span&gt; after &lt;span class="math"&gt;\(t\)&lt;/span&gt; seconds is given by &lt;span class="math"&gt;\(v(t) = 7 cos t - 5t^{cos t}\)&lt;/span&gt;, for &lt;span class="math"&gt;\(0 \leq t \leq 7\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The following diagram shows the graph of &lt;span class="math"&gt;\(v\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/temp_graph_v_vs_t.png" /&gt;
&lt;/div&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Find the initial velocity of &lt;span class="math"&gt;\(P\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find the maximum speed of &lt;span class="math"&gt;\(P\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Write down the number of times the acceleration of &lt;span class="math"&gt;\(P\)&lt;/span&gt; is &lt;span class="math"&gt;\(0\)&lt;/span&gt; &lt;span class="math"&gt;\(ms^{-2}\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;Find the acceleration of &lt;span class="math"&gt;\(P\)&lt;/span&gt; when the particle changes direction.&lt;/li&gt;
&lt;li&gt;Find the total distance travelled by &lt;span class="math"&gt;\(P\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 17</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq17-en.html" rel="alternate"/><published>2026-05-18T20:07:39+00:00</published><updated>2026-05-18T20:07:39+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq17-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 17&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(f(x) = Cos(e^x)\)&lt;/span&gt;, for &lt;span class="math"&gt;\(-2 \leq x \leq 2\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Find &lt;span class="math"&gt;\(f^\prime(x)\)&lt;/span&gt;.&lt;/li&gt;
&lt;li&gt;On the set of axes below, sketch the graph of &lt;span class="math"&gt;\(f^\prime(x)\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/grid_5_12.png" /&gt;
&lt;/div&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 18</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq18-en.html" rel="alternate"/><published>2026-05-18T20:04:46+00:00</published><updated>2026-05-18T20:04:46+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq18-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 18&lt;/p&gt;
</summary><content type="html">&lt;p&gt;A particle moves along a straight line with velocity &lt;span class="math"&gt;\(v = 12t - 2t^3 - 1\)&lt;/span&gt;,
for &lt;span class="math"&gt;\(t \geq 0\)&lt;/span&gt;, where &lt;span class="math"&gt;\(v\)&lt;/span&gt; is in centimetres per second and &lt;span class="math"&gt;\(t\)&lt;/span&gt; is in seconds.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Find the acceleration of the particle at time &lt;span class="math"&gt;\(t = 2.7\)&lt;/span&gt; seconds.&lt;/li&gt;
&lt;li&gt;Find the displacement of the particle after &lt;span class="math"&gt;\(1.3\)&lt;/span&gt; seconds.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 19</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq19-en.html" rel="alternate"/><published>2026-05-18T20:02:49+00:00</published><updated>2026-05-18T20:02:49+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq19-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 19&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(f(x) = ax^3 + bx^2 + c\)&lt;/span&gt;, where &lt;span class="math"&gt;\(a\)&lt;/span&gt;, &lt;span class="math"&gt;\(b\)&lt;/span&gt; and &lt;span class="math"&gt;\(c\)&lt;/span&gt; are real numbers.
The curve of &lt;span class="math"&gt;\(f\)&lt;/span&gt; passes through the point &lt;span class="math"&gt;\(( 2; 9 )\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple"&gt;
&lt;li&gt;Show that &lt;span class="math"&gt;\(8a + 4b +c = 9\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
&lt;p&gt;The curve of &lt;span class="math"&gt;\(f\)&lt;/span&gt; has a local minimum at &lt;span class="math"&gt;\((1; 4)\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha simple" start="2"&gt;
&lt;li&gt;Find two more equations in terms of &lt;span class="math"&gt;\(a\)&lt;/span&gt;, &lt;span class="math"&gt;\(b\)&lt;/span&gt; and &lt;span class="math"&gt;\(c\)&lt;/span&gt;,
giving your answers in a form similar to that of part A.&lt;/li&gt;
&lt;li&gt;Find the value of &lt;span class="math"&gt;\(a\)&lt;/span&gt;, the value of &lt;span class="math"&gt;\(b\)&lt;/span&gt; and the value of &lt;span class="math"&gt;\(c\)&lt;/span&gt;.&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 20</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq20-en.html" rel="alternate"/><published>2026-05-18T20:00:06+00:00</published><updated>2026-05-18T20:00:06+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq20-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 20&lt;/p&gt;
</summary><content type="html">&lt;p&gt;The gradient of a function is given by &lt;span class="math"&gt;\(\dfrac{dy}{dx} = 10e^{2x - 5}\)&lt;/span&gt;. When &lt;span class="math"&gt;\(x = 0\)&lt;/span&gt;, &lt;span class="math"&gt;\(y = 8\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Find the value of &lt;span class="math"&gt;\(y\)&lt;/span&gt; when &lt;span class="math"&gt;\(x = 1\)&lt;/span&gt;.&lt;/p&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 21</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq21-en.html" rel="alternate"/><published>2026-05-18T19:58:04+00:00</published><updated>2026-05-18T19:58:04+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq21-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 21&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Let &lt;span class="math"&gt;\(f(x) = e^x Sin 2x + 10\)&lt;/span&gt;, with &lt;span class="math"&gt;\(0 \leq x \leq 4\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Part of the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; is shown below.&lt;/p&gt;
&lt;p&gt;The figure is not to scale.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/etox_sin2x.png" /&gt;
&lt;/div&gt;
&lt;p&gt;Shown are an x-intercept at point &lt;span class="math"&gt;\(A\)&lt;/span&gt;, a local maximum at point &lt;span class="math"&gt;\(M\)&lt;/span&gt; with &lt;span class="math"&gt;\(x = p\)&lt;/span&gt; and a local minimum at point &lt;span class="math"&gt;\(N\)&lt;/span&gt; with &lt;span class="math"&gt;\(x = q\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha"&gt;
&lt;li&gt;&lt;p class="first"&gt;State the x-coordinate of &lt;span class="math"&gt;\(A\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;Find the value of&lt;/p&gt;
&lt;ol class="lowerroman simple"&gt;
&lt;li&gt;&lt;span class="math"&gt;\(p\)&lt;/span&gt;&lt;/li&gt;
&lt;li&gt;&lt;span class="math"&gt;\(q\)&lt;/span&gt;&lt;/li&gt;
&lt;/ol&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;Find &lt;span class="math"&gt;\(\int_p^qf(x)dx\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Explain why this is not the area of the shaded region.&lt;/p&gt;
&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry><entry><title>IB Calculus Problem 22</title><link href="https://blog.bernatchez.net/lang-version.en/calculusq22-en.html" rel="alternate"/><published>2026-05-18T19:55:55+00:00</published><updated>2026-05-18T19:55:55+00:00</updated><author><name>Annie Bernatchez</name></author><id>tag:blog.bernatchez.net,2026-05-18:/lang-version.en/calculusq22-en.html</id><summary type="html">&lt;p class="first last"&gt;Calculus problem 22&lt;/p&gt;
</summary><content type="html">&lt;p&gt;Consider &lt;span class="math"&gt;\(f(x) = x\ln(4 - x^2)\)&lt;/span&gt;, with &lt;span class="math"&gt;\(-2 &amp;lt; x &amp;lt; 2\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;Part of the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; is shown below.&lt;/p&gt;
&lt;div class="figure"&gt;
&lt;img alt="image essential to understanding the question" src="../images/xln4minuxsqr.png" /&gt;
&lt;/div&gt;
&lt;p&gt;Let &lt;span class="math"&gt;\(P\)&lt;/span&gt; and &lt;span class="math"&gt;\(Q\)&lt;/span&gt; be the points on the curve of &lt;span class="math"&gt;\(f\)&lt;/span&gt;
where the tangent to the graph of &lt;span class="math"&gt;\(f\)&lt;/span&gt; is
parallel to the x-axis.&lt;/p&gt;
&lt;ol class="upperalpha"&gt;
&lt;li&gt;&lt;ol class="first lowerroman"&gt;
&lt;li&gt;&lt;p class="first"&gt;Find the x-coordinates of &lt;span class="math"&gt;\(P\)&lt;/span&gt; and &lt;span class="math"&gt;\(Q\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;Consider &lt;span class="math"&gt;\(f(x) = k\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;State all values of &lt;span class="math"&gt;\(k\)&lt;/span&gt; for which there are exactly two solutions.&lt;/p&gt;
&lt;/li&gt;
&lt;/ol&gt;
&lt;/li&gt;
&lt;/ol&gt;
&lt;p&gt;Let &lt;span class="math"&gt;\(g(x) = x^3\ln(4 - x^2)\)&lt;/span&gt;, with &lt;span class="math"&gt;\(-2 &amp;lt; x &amp;lt; 2\)&lt;/span&gt;.&lt;/p&gt;
&lt;ol class="upperalpha" start="2"&gt;
&lt;li&gt;&lt;p class="first"&gt;Show that &lt;span class="math"&gt;\(g^\prime(x)=\frac{-2x^4}{4 - x^2} + 3x^2\ln(4 - x^2)\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;Sketch the graph of &lt;span class="math"&gt;\(g^\prime\)&lt;/span&gt;.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;&lt;p class="first"&gt;Consider &lt;span class="math"&gt;\(g^\prime(x) = w\)&lt;/span&gt;.&lt;/p&gt;
&lt;p&gt;State all values of &lt;span class="math"&gt;\(w\)&lt;/span&gt; for which there are exactly two solutions.&lt;/p&gt;
&lt;/li&gt;
&lt;/ol&gt;
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&lt;/script&gt;</content><category term="calculus"/><category term="IB"/><category term="question"/></entry></feed>