IB Calculus Problem 8

The following figure shows part of the graph of the quadratic function \(f\).

The figure is not to scale.

image essential to understanding the question

The x-intercepts are at \(( -4; 0 )\) and \(( 6; 0 )\) and the y-intercept is at \(( 0; 240 )\).

  1. Write down \(f(x)\) in the form \(f(x) = -10(x - p) (x - q)\).
  2. Find another expression for \(f(x)\) in the form \(f(x) = -10(x - h)^2 + k\).
  3. Show that \(f(x)\) can also be written as \(f(x) = 240 + 20x -10x^2\).
  4. A particle moves in a straight line such that its velocity \(v\) ( in \(ms^{-1}\) ), at time \(t\) (in seconds), is given by \(v = 240 + 20t -10t^2\) , for \(0 \leq t \leq 6\).
    1. Find the value of \(t\) when the velocity of the particle is greatest.
    2. Find the acceleration of the particle when its velocity is zero.
Published by Annie Bernatchez in «calculus». Key Words: IB, question